# Miraculous world of Numbers

Miraculous World of Numbers is an eBook on Mathematical Fun. It has so many creative ideas to develop the skills & to increase the Thinking power. Along with this eBook I would like to encourage Students & Parents how they can participate to build the entire world with powerful thinking level. My Blogs will definitely encourage students & parents in this direction.

## Saturday, December 10, 2022

### 136-Number pattern and its beauty

## Sunday, November 27, 2022

### 135-Magic cube part-6

## Thursday, November 24, 2022

### 134-Important video on Simple method of multiplication

Video on a simple method of multiplication.

For more details on multiplication, click on the following link:

## Click here for the previous blog on a simple method of multiplication

Example: Multiply 279 by 563.

## Step-1

## Saturday, November 19, 2022

### 133-Important video on fun with mathematics

^{2}, 33

^{2}, 333

^{2,}and so on.

^{2}, 66

^{2}, 666

^{2,}and so on.

^{2}, 99

^{2}, 999

^{2,}and so on.

## Click here to see the video on the fun with mathematics

## Tuesday, November 8, 2022

### 132-Magic cube part-5

## Click here for the previous blog on magic cube.

We have already seen the preparation of the magic cube.

Today we will discuss some specific addition patterns of this magic cube. See the following figure of the magic cube.

Here the addition of all the corresponding numbers will be 1164.

## Click here for the next blog on magic cube.

## Sunday, May 1, 2022

### 131-Miraculous Constant 8181

## Miraculous Constant 8181

**This work is a special birthday gift to my sweetheart, my wife Jyoti Satpute**

1) Place the largest digit at the 1000’s place and the smallest digit at the 100’s place.

Out of the remaining 2 digits:

2) Place the largest digit at the 10’s place and the smallest digit at the unit place.

Example: Let’s say the input number is 8492. Let’s form the Zigzag number from this.

1) The highest digit of the given number 8492 is 9 and the smallest digit is 2. So, the 1000’s placed digit of the Zigzag number will be 9, and the 100’s placed digit will be 2.

**∀ a, b, c, d ∈**

**W, a set of whole numbers,**then the Zigzag number will be 1000a + 100d + 10b + c and its reverse number is 1000c + 100b + 10d + a. At least one digit out of a, b, c, or d must be different from others.

Repeat this process called iteration until you get 8181 (Miraculous constant).

**Introduction**

**Method**

**Figure-1**

*The number of iterations for 8492 to get the Miraculous Constant 8181 is 8.*