In continuation of part - 7, we will see all the important formulas and useful statements which are to be used in the Math test GRE.
Factorization (Continued):
b) Factorization of Polynomial (Continued):
3) Synthetic Division:
Example 2: Divide 4x6-20x5+7x2-46x+55 by (x-5) using the synthetic division method.
Solution:
1) Write all the terms in descending order:
4x6-20x5+0x4+0x3+7x2-46x+55
2) Write this polynomial in the coefficient form:
[4, -20, 0, 0, 7, -46, 55]
3) Now we will see the division using the synthetic division method.
a) Here the divisor is (x-5) so we have x-5=0, x=5.
c) So we have 4x6-205+7x2-46x+55 = (x-5) (4x5+7x-11)+0.
Example 3: Divide 5x5+20x4-2x3-8x2+3x+15 by (x+4) using the synthetic division method.
Solution:
1) Write all the terms in descending order:
5x5+20x4-2x3-8x2+3x+15
2) Write this polynomial in the coefficient form:
[5, 20, -2, -8, 3, 15]
3) Now we will see the division using the synthetic division method.
a) Here the divisor is (x+4) so we have x+4=0, x=-4.
b) Here the quotient is 5x5+20x4-2x3-8x2+3x+15. Here the remainder is 3.
c) So we have 5x5+20x4-2x3-8x2+3x+15 = (x+4) (5x4-2x2+3)+3.
1) Write all the terms in descending order:
5x5+20x4-2x3-8x2+3x+15
2) Write this polynomial in the coefficient form:
[5, 20, -2, -8, 3, 15]
3) Now we will see the division using the synthetic division method.
a) Here the divisor is (x+4) so we have x+4=0, x=-4.
b) Here the quotient is 5x5+20x4-2x3-8x2+3x+15. Here the remainder is 3.
c) So we have 5x5+20x4-2x3-8x2+3x+15 = (x+4) (5x4-2x2+3)+3.
In the next part, we will see a few examples and some essential formulae.
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