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In the Previous Blog, we had seen some important concepts of Arithmetic & Geometric Progression.
In this Blog, we Describe the Important Formulas of an AP & GP.
1) tn = a + (n - 1) d
2) Sn = n * (a + l)/2
3) Sn = n * [ 2 a + (n - 1) d ) ] / 2
Now we will see some examples:
Problems related to tn = a + (n - 1) d:
A) Find the nth term of an AP 3, 5, 7, 9 ...
Solution:
1) Here a = 3, d = (5 - 3) = 2 so, d = 2.
2) We know that
Now we will see some examples:
Problems related to tn = a + (n - 1) d:
A) Find the nth term of an AP 3, 5, 7, 9 ...
Solution:
1) Here a = 3, d = (5 - 3) = 2 so, d = 2.
2) We know that
tn = a + (n -1) d
= 3 + (n -1) (2)
= 3 + (2 n - 2)
= 1 + (2 n)
= (2 n) + 1
3) Answer: Here the nth term of an AP is tn = (2 n) + 1
B) Find the first term of an AP in which d = 4 and its 100th term is 403.
= 3 + (n -1) (2)
= 3 + (2 n - 2)
= 1 + (2 n)
= (2 n) + 1
3) Answer: Here the nth term of an AP is tn = (2 n) + 1
B) Find the first term of an AP in which d = 4 and its 100th term is 403.
Solution:
1) Here d = 4 and t100 = 403.
2) We know that
1) Here d = 4 and t100 = 403.
2) We know that
tn = a + (n -1) d
403 = a + (100 - 1)*(4)
403 = a + (99)*(4)
403 = a + (396)
a = 403 - 396
a = 7
3) Answer: Here the 1st term is a = 7
C) If the nth term of an AP is m and the mth term of an AP is n, then find the value of d.
403 = a + (100 - 1)*(4)
403 = a + (99)*(4)
403 = a + (396)
a = 403 - 396
a = 7
3) Answer: Here the 1st term is a = 7
C) If the nth term of an AP is m and the mth term of an AP is n, then find the value of d.
Solution:
1) Let " a " be the 1st term and " d " be a common difference.
2) We know that
1) Let " a " be the 1st term and " d " be a common difference.
2) We know that
tn = a + (n -1) d
3) So we,
tn = a + (n -1) d = m ----------- (1)
tm = a + (m -1) d = n ----------- (2)
Subtract equation (2) from (1) we get,
a + (n -1) d = m
a + (m -1) d = n
(-) (-) (-)
----------------------------------
(n - 1 - m + 1) * d = (m - n)
(n - m) * d = (m - n)
d = (m - n)/(n-m)
d = - 1
4) Answer: Here the common difference is d = - 1
3) So we,
tn = a + (n -1) d = m ----------- (1)
tm = a + (m -1) d = n ----------- (2)
Subtract equation (2) from (1) we get,
a + (n -1) d = m
a + (m -1) d = n
(-) (-) (-)
----------------------------------
(n - 1 - m + 1) * d = (m - n)
(n - m) * d = (m - n)
d = (m - n)/(n-m)
d = - 1
4) Answer: Here the common difference is d = - 1
In the next part, we will see a few examples and some essential formulae.
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