176-NCERT-10-8-Introduction to Trigonometry - Ex- 8.3

NCERT

10th Mathematics

Exercise 8.3

Topic: 8 Introduction to Trigonometry

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EXERCISE 8.3

Q 1. Express the trigonometric ratios sin A, sec A, and tan A in terms of cot A.

Solution:

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Q 3. Choose the correct option. Justify your choice.

(i) 9 sec² A – 9 tan² A =

(A) 1 (B) 9 (C) 8 (D) 0

(ii) (1 + tan θ + sec θ) (1 + cot θ – cosec θ) =

(A) 0 (B) 1 (C) 2 (D) –1

(iii) (sec A + tan A) (1 – sin A) =

(A) sec A (B) sin A (C) cosec A (D) cos A

(iv) [1 + tan² A] / [1 + cot² A] =

(A)  sec² A (B) –1 (C) cot² A (D) tan² A

Solution:

Ans:

Solution:

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